(x^2)+3x+2=x+1

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Solution for (x^2)+3x+2=x+1 equation: 



(x^2)+3x+2=x+1

We move all terms to the left:

(x^2)+3x+2-(x+1)=0

We get rid of parentheses

x^2+3x-x-1+2=0

We add all the numbers together, and all the variables

x^2+2x+1=0

a = 1; b = 2; c = +1;
Δ = b2-4ac
Δ = 22-4·1·1
Δ = 0
Delta is equal to zero, so there is only one solution to the equation

                              Stosujemy wzór:
$x=\frac{-b}{2a}=\frac{-2}{2}=-1$

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